Interpret:How do I declare the Swift closure?

Today, a friend recommended an interesting page,A domain name is like:

http://fuckingclosuresyntax.com

In the Swift,All functions are closures,Standard functions are just the most complete closures name with parameters。

All right,The following is the text


 

 

As avariable:


 

As aOptional variable:

 

As aType alias:

 

As aconstant:

 

As aWhen the function call parameters:

 

As aFunction parameters:

 

As aAnd using the parameters of the function type inference:

 

As aEstimation function parameters and return type:

 

As aThe last parameter of the function:

 

As the last parameter to the functionParameter names and abbreviations:

 

And as a function of the last parameterAnd concluded that the return value:

 

As the last parameter to the function,A presence function as a reference:

 

As a function parameterWith default capture:

 

As a function parameterWith default parameters to infer the type of capture and return type and:

 

This site does not list ready to use all closures。
By Zev Eisenberg, Yes, that's right Mike Walker Sorry, The latter is unlikely to have a good impression on these things。

Original article written by Gerber drop-off:R0uter's Blog » Interpret:How do I declare the Swift closure?

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The non-declaration,I have written articles are original,Reproduced, please indicate the link on this page and my name。

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